Integrand size = 25, antiderivative size = 121 \[ \int \frac {(c x)^m \left (A+B x+C x^2\right )}{a+b x^2} \, dx=\frac {C (c x)^{1+m}}{b c (1+m)}+\frac {(A b-a C) (c x)^{1+m} \operatorname {Hypergeometric2F1}\left (1,\frac {1+m}{2},\frac {3+m}{2},-\frac {b x^2}{a}\right )}{a b c (1+m)}+\frac {B (c x)^{2+m} \operatorname {Hypergeometric2F1}\left (1,\frac {2+m}{2},\frac {4+m}{2},-\frac {b x^2}{a}\right )}{a c^2 (2+m)} \]
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Time = 0.09 (sec) , antiderivative size = 121, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.120, Rules used = {1816, 822, 371} \[ \int \frac {(c x)^m \left (A+B x+C x^2\right )}{a+b x^2} \, dx=\frac {(c x)^{m+1} (A b-a C) \operatorname {Hypergeometric2F1}\left (1,\frac {m+1}{2},\frac {m+3}{2},-\frac {b x^2}{a}\right )}{a b c (m+1)}+\frac {B (c x)^{m+2} \operatorname {Hypergeometric2F1}\left (1,\frac {m+2}{2},\frac {m+4}{2},-\frac {b x^2}{a}\right )}{a c^2 (m+2)}+\frac {C (c x)^{m+1}}{b c (m+1)} \]
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Rule 371
Rule 822
Rule 1816
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {C (c x)^m}{b}+\frac {(c x)^m (A b-a C+b B x)}{b \left (a+b x^2\right )}\right ) \, dx \\ & = \frac {C (c x)^{1+m}}{b c (1+m)}+\frac {\int \frac {(c x)^m (A b-a C+b B x)}{a+b x^2} \, dx}{b} \\ & = \frac {C (c x)^{1+m}}{b c (1+m)}+\frac {B \int \frac {(c x)^{1+m}}{a+b x^2} \, dx}{c}+\frac {(A b-a C) \int \frac {(c x)^m}{a+b x^2} \, dx}{b} \\ & = \frac {C (c x)^{1+m}}{b c (1+m)}+\frac {(A b-a C) (c x)^{1+m} \, _2F_1\left (1,\frac {1+m}{2};\frac {3+m}{2};-\frac {b x^2}{a}\right )}{a b c (1+m)}+\frac {B (c x)^{2+m} \, _2F_1\left (1,\frac {2+m}{2};\frac {4+m}{2};-\frac {b x^2}{a}\right )}{a c^2 (2+m)} \\ \end{align*}
Time = 0.14 (sec) , antiderivative size = 99, normalized size of antiderivative = 0.82 \[ \int \frac {(c x)^m \left (A+B x+C x^2\right )}{a+b x^2} \, dx=\frac {x (c x)^m \left (a C (2+m)+b B (1+m) x \operatorname {Hypergeometric2F1}\left (1,1+\frac {m}{2},2+\frac {m}{2},-\frac {b x^2}{a}\right )+(A b-a C) (2+m) \operatorname {Hypergeometric2F1}\left (1,\frac {1+m}{2},\frac {3+m}{2},-\frac {b x^2}{a}\right )\right )}{a b (1+m) (2+m)} \]
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\[\int \frac {\left (c x \right )^{m} \left (C \,x^{2}+B x +A \right )}{b \,x^{2}+a}d x\]
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\[ \int \frac {(c x)^m \left (A+B x+C x^2\right )}{a+b x^2} \, dx=\int { \frac {{\left (C x^{2} + B x + A\right )} \left (c x\right )^{m}}{b x^{2} + a} \,d x } \]
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Result contains complex when optimal does not.
Time = 2.31 (sec) , antiderivative size = 291, normalized size of antiderivative = 2.40 \[ \int \frac {(c x)^m \left (A+B x+C x^2\right )}{a+b x^2} \, dx=\frac {A c^{m} m x^{m + 1} \Phi \left (\frac {b x^{2} e^{i \pi }}{a}, 1, \frac {m}{2} + \frac {1}{2}\right ) \Gamma \left (\frac {m}{2} + \frac {1}{2}\right )}{4 a \Gamma \left (\frac {m}{2} + \frac {3}{2}\right )} + \frac {A c^{m} x^{m + 1} \Phi \left (\frac {b x^{2} e^{i \pi }}{a}, 1, \frac {m}{2} + \frac {1}{2}\right ) \Gamma \left (\frac {m}{2} + \frac {1}{2}\right )}{4 a \Gamma \left (\frac {m}{2} + \frac {3}{2}\right )} + \frac {B c^{m} m x^{m + 2} \Phi \left (\frac {b x^{2} e^{i \pi }}{a}, 1, \frac {m}{2} + 1\right ) \Gamma \left (\frac {m}{2} + 1\right )}{4 a \Gamma \left (\frac {m}{2} + 2\right )} + \frac {B c^{m} x^{m + 2} \Phi \left (\frac {b x^{2} e^{i \pi }}{a}, 1, \frac {m}{2} + 1\right ) \Gamma \left (\frac {m}{2} + 1\right )}{2 a \Gamma \left (\frac {m}{2} + 2\right )} + \frac {C c^{m} m x^{m + 3} \Phi \left (\frac {b x^{2} e^{i \pi }}{a}, 1, \frac {m}{2} + \frac {3}{2}\right ) \Gamma \left (\frac {m}{2} + \frac {3}{2}\right )}{4 a \Gamma \left (\frac {m}{2} + \frac {5}{2}\right )} + \frac {3 C c^{m} x^{m + 3} \Phi \left (\frac {b x^{2} e^{i \pi }}{a}, 1, \frac {m}{2} + \frac {3}{2}\right ) \Gamma \left (\frac {m}{2} + \frac {3}{2}\right )}{4 a \Gamma \left (\frac {m}{2} + \frac {5}{2}\right )} \]
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\[ \int \frac {(c x)^m \left (A+B x+C x^2\right )}{a+b x^2} \, dx=\int { \frac {{\left (C x^{2} + B x + A\right )} \left (c x\right )^{m}}{b x^{2} + a} \,d x } \]
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\[ \int \frac {(c x)^m \left (A+B x+C x^2\right )}{a+b x^2} \, dx=\int { \frac {{\left (C x^{2} + B x + A\right )} \left (c x\right )^{m}}{b x^{2} + a} \,d x } \]
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Timed out. \[ \int \frac {(c x)^m \left (A+B x+C x^2\right )}{a+b x^2} \, dx=\int \frac {{\left (c\,x\right )}^m\,\left (C\,x^2+B\,x+A\right )}{b\,x^2+a} \,d x \]
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